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cal 3discreteodeenv systems

On this page

  • 1. What is a vector and why do we treat it differently?
  • 2. Graphical vs. analytical methods
  • 3. Breaking a vector into components
  • 4. Reassembling components
  • 5. Unit-vector notation
  • 6. Adding or subtracting vectors with components
  • 7. Quick self-check
  • Key take-aways

Mechanics

Chapter 3: Vectors and Coordinate Systems

Evan Luo · May 17, 2025

Mechanics

Chapter 3: Vectors and Coordinate Systems

Evan LuoMay 17, 2025

3 min read

1. What is a vector and why do we treat it differently?

A scalar (like mass or temperature) only has a size. A vector has size + direction—so where it points matters. Whenever we add or subtract several vectors, the single vector that replaces them is called the resultant. Graphically we find it by placing vectors tip-to-tail; draw one arrow’s tail at the previous arrow’s tip, then join the first tail to the last tip for the resultant direction .


2. Graphical vs. analytical methods

Tip-to-tail drawings are great for visualising but impractical for calculations—a small protractor error gives a big numeric error. Instead, physicists switch to an analytical (component-based) method inside a Cartesian xxx–yyy (and sometimes zzz) grid .


3. Breaking a vector into components

Place the vector so its tail sits at the origin. Using basic trigonometry:

Ax=Acos⁡θ,Ay=Asin⁡θA_x = A\cos\theta, \qquad A_y = A\sin\thetaAx​=Acosθ,Ay​=Asinθ

where θ\thetaθ is measured from the xxx-axis. Think of AxA_xAx​ and AyA_yAy​ as the “shadows” the arrow casts on the axes .

Sign hints: • Quadrant tells you plus/minus for each component. • Your calculator’s tan⁡−1\tan^{-1}tan−1 only returns angles between −90∘-90^\circ−90∘ and +90∘+90^\circ+90∘; always check the signs afterward .


4. Reassembling components

Need the size and overall direction back? Reverse the process:

A=Ax 2+Ay 2,θ=tan⁡−1 ⁣(AyAx)A = \sqrt{A_x^{\,2}+A_y^{\,2}}, \qquad \theta = \tan^{-1}\!\left(\frac{A_y}{A_x}\right)A=Ax2​+Ay2​​,θ=tan−1(Ax​Ay​​)

Again, adjust θ\thetaθ into the correct quadrant .


5. Unit-vector notation

An even cleaner way to write vectors is with unit vectors ı^,ȷ^,k^\hat{\mathbf ı},\hat{\mathbf ȷ},\hat{\mathbf k}ı^,ȷ^​,k^ that each point one unit along an axis:

A=Axı^+Ayȷ^  (+ Azk^)\mathbf A = A_x\hat{\mathbf ı} + A_y\hat{\mathbf ȷ}\; (\text{+}\,A_z\hat{\mathbf k})A=Ax​ı^+Ay​ȷ^​(+Az​k^)

The little “hats” just tell direction; the numbers in front still hold the size .


6. Adding or subtracting vectors with components

  1. Decompose every vector into xxx and yyy pieces.
  2. Add or subtract all xxx-components to get CxC_xCx​; do the same for yyy to get CyC_yCy​.
  3. Re-assemble CxC_xCx​ and CyC_yCy​ into your final resultant C\mathbf CC just like in Section 4 .

7. Quick self-check

Problem: A delivery drone flies 25m25 \text{m}25m at 35∘35^\circ35∘ above + xxx (east) and then 18m18 \text{m}18m due north. a) What are the components of each leg? b) Find the drone’s total displacement (magnitude & direction).

Solution sketch

Leg 1

Ax=25cos⁡35∘≈20.5 m,  Ay=25sin⁡35∘≈14.3 mA_x=25\cos35^\circ\approx20.5\text{ m},\; A_y=25\sin35^\circ\approx14.3\text{ m}Ax​=25cos35∘≈20.5 m,Ay​=25sin35∘≈14.3 m

Leg 2 (Bx=0,  By=18 mB_x=0,\;B_y=18\text{ m}Bx​=0,By​=18 m)

Add components: Cx=Ax+Bx=20.5 m,  Cy=Ay+By=32.3 mC_x=A_x+B_x=20.5\text{ m},\;C_y=A_y+B_y=32.3\text{ m}Cx​=Ax​+Bx​=20.5 m,Cy​=Ay​+By​=32.3 m

Magnitude: C=20.52+32.32≈38.3 mC=\sqrt{20.5^{2}+32.3^{2}}\approx38.3\text{ m}C=20.52+32.32​≈38.3 m

Direction: θ=tan⁡−1 ⁣(32.320.5)≈57∘\theta=\tan^{-1}\!\left(\dfrac{32.3}{20.5}\right)\approx57^\circθ=tan−1(20.532.3​)≈57∘ north of east.

Click to reveal

Key take-aways

  • Vectors differ from scalars because direction counts.
  • Use components (and unit-vector notation) to turn messy 2-D vector problems into two neat 1-D problems.
  • Always track signs and quadrants.
  • Rebuild the magnitude and angle only after finishing all component math.

Source: https://notes.ohevan.com/notes/mechanics/03-vectors-and-coordinate-systems

© 2026 Evan Luo. All rights reserved.

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